y-2/y-9+y^2-19y+34/y^2-10y+9=y-3/y-1

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Solution for y-2/y-9+y^2-19y+34/y^2-10y+9=y-3/y-1 equation: 



y-2/y-9+y^2-19y+34/y^2-10y+9=y-3/y-1

We move all terms to the left:

y-2/y-9+y^2-19y+34/y^2-10y+9-(y-3/y-1)=0



Domain of the equation: y!=0

y∈R





Domain of the equation: y^2!=0

y^2!=0/

y^2!=√0

y!=0

y∈R





Domain of the equation: y-1)!=0

y∈R



We add all the numbers together, and all the variables

y^2-28y-2/y+34/y^2-(y-3/y-1)=0

We get rid of parentheses

y^2-28y-2/y+34/y^2-y+3/y+1=0

We calculate fractions

We do not support eypression: y^3

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